Simple Mains Powered LED Light Circuit

Simple Mains Powered LED Light Circuit runs on 230V AC mains.

It uses capacitor dropper to limit the current.

LEDs in series-parallel are cheap and easy for mains lighting.

They are with bright white light and no big transformer.

It is good for low power light needs.

Circuit Working:

Parts List:

Circuit changes high AC to safe DC for LEDs.

Below are the circuit working for each circuit parts:

C1 Capacitor dropper: Limits current safely using reactance and not resistors and it stops overheating.

Resistor R1: Discharges C1 after unplugging and prevents shock.

D1 to D4 (Bridge rectifier): Turns AC into pulsating DC by using both halves of AC wave.

C2 (Smoothing capacitor): Smooths DC, reduces LED flicker and improves life.

Resistor R2: Limits surge current to LEDs and stops damage.

LED1 to LED12: Parallel groups share voltage and current evenly for bright light.

Formulas with Calculations:

Formulas and calcultions for mains LED light:

Capacitor Reactance C1:

Xc = 1 / (2πfC)

where,

• C = 1µF and f = 50Hz

Xc = 3185Ω

Circuit Current:

I = V / Xc

230V / 3185Ω = 0.0723A (72mA) which is enough for LEDs

Power in R2:

P = I² × R

(0.0723)² × 56Ω = 0.29W this is higher than 0.25W limit, so use 2W resistor

How to Build:

To build a Simple Mains Powered LED Light Circuit following steps are required for connections of the circuit

• Gather all parts as per circuit diagram
• Connect AC input to 230V mains.
• Put C1 in series with live wire to drops voltage.
• Put R1 parallel to C1 to discharge safety.
• Add D1 to D4 bridge rectifier from AC to DC.
• Put C2 across rectifier output which is the smooth voltage.
• Add R2 in series with limit LED current.
• Connect LED1 to LED12 in parallel groups.

Conclusion:

Simple Mains Powered LED Light Circuit is and easy to make project.

It is cheap, transformer free LED light using capacitor dropper.

It is good for night lamps, emergency lights and indicators.

References:

Mains Operated LED Light Circuit Working