Simple 12V Boost Converter Circuit using IC LM2698 make output voltage higher than input, also LM2698 IC have switch inside and can handle 18V and 1.35A with 0.2Ω.
Here, the input voltage is from 2.2V to 17V and output is 2.2V to 17V and it keeps voltage steady even if input changes.
Circuit is good for many input voltages and battery devices, for example 5V input convert to 12V output; also this article shows how circuit work, design calculation and to make 12V boost with LM2698.
Circuit Working:
Parts List:
| Components | Values | Quantity |
|---|---|---|
| Resistors (All resistors are 1/4 watt unless specified) | 25k | 1 |
| 30k | 1 | |
| 3.5k | 1 | |
| Capacitors | Ceramic 4.7nF | 1 |
| Electrolytic 22µF 25V | 1 | |
| Electrolytic 10µF 25V | 1 | |
| Semiconductors | IC LM2698 | 1 |
| 1N5819 Schottky Diode | 1 | |
| Inductor 10µH | 1 |
IC LM2698 is switching regulator and make input higher and steady to12V output, also pin 6 power input works with 4.5V to 5.5V DC.
Do not connect load more than 400mA, as chip gives max 400mA at 12V only.
Inductor L1 save energy when LM2698 switch ON.
When switch is OFF then energy goes through diode D1 to charge C3 and keep output steady to 12V; then feedback R2 and R3 control output by changing switch ON time.
Finally, pin 3 SHDN connect to GND to turn circuit OFF.
Formulas:
Formula for output voltage:
Vout = 1.26V * (1 + R2 / R3)
where,
- Vout is output voltage
- 1.26V is inside reference voltage in IC
- R2 and R3 are resistors for voltage divider
How to Build:
To build a Simple 12V Boost Converter Circuit using IC LM2698 follow below steps for connection:
- First, get all parts like in circuit diagram.
- Next, connect pin 1 of IC1 to GND with resistor R1 and capacitor C1.
- After that, connect pin 2 of IC1 to 12V output (Vout) through resistor R2, also connect resistor R2 from pin 2 to GND.
- Then pin 3 is shutdown pin and connect to ground to turn OFF the circuit.
- Now connect pin 4 and pin 7 of IC1 to GND.
- Also, connect inductor L1 between pin 5 and pin 6 of IC1 and then connect capacitor C2 from pin 6 to GND.
- Further, connect diode D1 between pin 5 and other side of resistor R2.
- Next, connect input voltage from 4.5V to 5.5V to joint of pin 6, L1 and positive of C2.
- Lastly, connect positive of capacitor C3 to one side of resistor R2 and negative of C3 to GND.
Conclusion:
To conclude, the IC LM2698 makes this simple 12V boost converter circuit a good step-up solution for low input voltages.
In addition, with right parts it gives steady 12V output for many projects and also, IC LM2698 is efficient and easy to use and is best for battery devices and power management.