Simple 3V to 9V DC Boost Converter Circuit

This 3V to 9V DC boost converter circuit is like a superhero for your batteries.

It can take a weak 3V battery, like a dead one in your remote, and jumpstart it to a powerful 9V which is what many devices need to run.

This is perfect for situations where you only have low voltage batteries available but still need to power your electronics.

Circuit Working:

Parts List:

Here is a DC boost converter circuit ranging from 3V to 9V, these converters can be useful when a 9V battery is not available or if you find them too expensive.

The first circuit is quite simple, utilizing the TL496 power supply controller a coil, and an electrolytic capacitor.

It can provide a maximum output voltage of 8.6V and a current of approximately 80mA.

At maximum output current, the input current drawn from the batteries is 405mA.

When there is no load, the current consumption is 125µA, and the battery life is around 166 days.

The basic principle of operation involves using an inductor and a switching element i.e IC to periodically store energy from the input voltage in the inductor and then release it to the output at a higher voltage.

This process is controlled by a feedback mechanism to regulate the output voltage to the desired level.

Boost converter circuits can vary in complexity and components used, but they generally include an inductor, a switching elements like IC, capacitors and sometimes a feedback network for voltage regulation.

The efficiency and performance of the circuit depend on the choice of components and the design of the circuit.

Formulas:

Although precise computations for component values in this particular circuit could necessitate comprehensive datasheet information for the TL496 IC, we can offer some basic boost converter related formulas:

Duty Cycle D:

D = (V_out – V_in) / V_out

where,

• D stands for duty cycle, or the proportion of on time to total switching time.
• The intended output voltage, Vout in this case is 9V.
• The input voltage, or Vin in this instance, is 3V.

Inductor Value L:

L = (V_in * D * t_on) / Δ_IL

where,

• L represents the inductors inductance,
• t_on represents the MOSFETs on time and
• Δ_IL is the required inductor current ripple.

Note:

These equations give a general idea of how the parts of a boost converter relate to one another.

More intricate factors are taken into account during the actual component values and design process, which frequently calls for repeated computations and simulations.

How to build:

To build a Simple 3V to 9V DC Boost Converter Circuit follow the below mentioned steps:

• Connect Pin 2 of the TL496 to the positive terminal of the battery.
• Connect Pin 5 and pin 7 of the TL496 to the negative terminal of the battery.
• Connect Pin 6 of the TL496 to Pin 2 to positive terminal battery. .
• Connect Pin 8 of the TL496 to output of 9V.
• Connect a capacitor 470µF to ground through pin 8.

Note:

• This circuit involves the use of electronic components and soldering.
• Exercise caution and follow safety guidelines when working with electricity.

Conclusion:

A 3V to 9V DC boost converter circuit is a versatile and essential component in many electronic devices, especially those powered by batteries or other low-voltage sources.

By efficiently stepping up the voltage these circuits enable the use of higher voltage components, ensuring proper operation of the device.

Whether in portable electronics or other applications requiring voltage step up, these converters play a crucial role in maintaining functionality and performance.

References:

3.7V to 9V DC to DC boost step-up converter design help!