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Simple Thermistor Based Fire Alarm Circuit

This Simple Thermistor Based Fire Alarm Circuit is very small, simple and smart.

It uses a thermistor to sense heat fast.

When temperature goes high the circuit wakes up and makes loud sound.

No microcontroller, no complex parts.

Only few components and we get a working fire alert that anyone can build at home

Circuit Working:

Parts List:

Part NameValueQuantity
Resistors1k 1/4 watt1
560Ω 1/4 watt1
Thermistor 10k NTC1
SemiconductorsTransistor BC547 NPN1
Diode 1N40071
Speaker 8Ω small speaker1
Power Supply +6V DC1

The 10k thermistor and R1 resistor make a voltage divider.

At normal temperature, thermistor has high resistance.

Voltage at the divider midpoint is low.

The D1 diode 1N4007 passes this voltage to the R2 base resistor.

The Q1 transistor base gets very small current, so transistor stays OFF.

Speaker stays silent.

When temperature rises, thermistor resistance drops.

Voltage at midpoint becomes higher.

More current reaches the transistor base through the R2 resistor.

Transistor turns ON.

Speaker receives current and makes alarm sound.

Formulas:

Below is the Thermistor divider voltage formula:

Vout = Vin × Rfixed / (Rthermistor + Rfixed)

where,

As thermistor resistance changes, Vout changes.

The formula shows the midpoint voltage when the thermistor value changes with heat.

How to Build:

To build a Simple Thermistor Based Fire Alarm Circuit follow the below connection steps:

Conclusion:

This Simple Thermistor Based Fire Alarm Circuit is easy small to build.

It uses very basic parts and still work good when heat goes high.

It is a good project to learn sensor and transistor ON and OFF action.

Circuit can improve later by adding buzzer, relay or better heat setting.

References:

FIRE ALARM A PROJECT REPORT

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