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Simple USB to 12V DC Boost Converter Circuit

This simple USB to 12V DC boost converter circuit works as a DC-DC step-up converter.

It takes power from a USB port that gives 5V DC and increases it to 12V DC.

This circuit is really useful for powering small 12V devices using a regular USB source, like a power bank or a computers USB port.

At its heart the circuit uses the LT1618 boost converter integrated circuit, which is well-known for efficiently changing a lower voltage into a higher one while keeping everything stable.

The IC has a wide input voltage range, from 1.8 to 18V DC and can provide an output voltage of up to 35V DC.

Circuit Working:

Parts List:

Component TypeValue/Part NumberQuantity
Resistors( All resistors are 1/4 watt unless specified)909k1
107k1
13k1
2k1
20k1
0.1Ω1
CapacitorsCeramic 10nF 1
Electrolytic 4.7µF 25V2
SemiconductorsIC LT1618 1
Transistor BS1701
Schottky Diode MBR0520 1
Inductor10µH1

The LT1618 chip is the key part that boosts voltage levels.

When you connect a 5V direct current the inductor L1 stores energy while the chips internal switch is on.

When the switch turns off the stored energy is released through the Schottky diode D1 which increases the output voltage.

Pin 9 is for shutting down the chip, if it gets less than 0.3V the chip will turn off.

Pin 4 is for adjusting the current sense, you can lower the current sense voltage by putting a DC voltage on this pin.

The circuit gets 5V DC power from a USB port.

To keep the input voltage steady and reduce noise capacitor C3 is used.

The LT1618 chip along with inductor L1 and diode D1 successfully raises the voltage to 12V DC.

A voltage divider made of resistors R1 and R2 sends feedback to the chip helping it keep the output voltage at the right level.

The transistor Q1 allows for external control of the circuit through the shutdown (SHDN) pin.

Formulas with Calculations:

Output Voltage Calculation:

Vout = 1.23V × (1 + R1/R2)

where,

Substituting values:

R1 = 909k and R2 = 107k:

Vout = 1.23V × (1 + 909k / 107k)

Vout = 12V

Feedback Voltage Divider Calculation:

The feedback voltage is determined using resistors R1 and R2 forming a divider network:

Vfb = Vout × (R2 / (R1 + R2))

where,

These calculations ensure that the circuit provides a stable 12V output from a 5V USB source.

How to Build:

To build a Simple USB to 12V DC Boost Converter Circuit follow the below mentioned steps for connections and assembling:

Conclusion:

Simple USB to 12V DC Boost Converter Circuit is a smart way to create 12V DC from a regular 5V USB source.

It is great for small electronic projects that need 12V but still want to be portable.

The IC LT1618 ensures high efficiency and by using an external transistor you can have more control over the output.

References:

Datasheet IC LT1618

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