Make your led blink easy with this easy to make Low Power Led Flasher Circuit using Nand Gate IC
It uses IC CD 4093, a quad Nand gate with Schmitt trigger input.
Circuit makes led blink with very less power and it can run from small 6V battery also.
Circuit Working:
Parts List:
| Component type | Value | quantity |
|---|---|---|
| Resistors | 330k ohm 1/4 watt | 1 |
| 330 ohm 1/4 watt | 1 | |
| Capacitors | Electrolytic 10uF 10V or 16V | 2 |
| Semiconductors | IC CD 4093 | 1 |
| Diode 1N4148 | 1 | |
| LED any color | 1 | |
| Battery 6V | 1 |
The above circuit diagram uses one nand gate from CD 4093.
This IC have 4 nand gates inside and pin 1,2,8,9,12,13 are joined so they act like inverter.
Capacitor C1 and resistor R1 make timing network.
When power is ON, C1 capacitor charge through R1 and diode D1.
This makes input change slow and Schmitt trigger make output change fast after one level.
So led blink ON and OFF.
Diode D1 gives fast discharge for C1 so duty cycle is correct.
Resistor R2 limit current of LED
Formula:
Formula for time period t = 0.693 × R1 × C1
Frequency f = 1 / t
here,
- R1 is 330k
- C1 is 10uF
t = 0.693 × 330000 × 0.00001 = 2.28 seconds approx
So LED will flash around every 2.3 second
How to Build:
To build a Low Power Led Flasher Circuit using Nand Gate IC following are the steps to follow:
- Take all parts same like in circuit picture.
- Connect pin 1,2,8,9,12,13 of IC 4093 to + of 6V battery and + of capacitor C2 and negative of C2 goes to ground.
- Connect pin 7 of IC to ground.
- Connect pin 14 of IC to + of 6v battery.
- Connect pin 4 of IC to point of diode D1, resistor R2 and anode of LED.
- Join pin 5 and pin 6 together.
- Put diode D1 and resistor R1 between pin 4 and pin 6.
- Connect + of capacitor C1 to cathode of LED and negative of C1 goes to ground.
Conclusion:
This is a very low cost and Low Power Led Flasher Circuit using Nand Gate IC
It uses only one IC, two capacitors, two resistors, one diode and one led.
This circuit can be used in small toys, indicators and hobby projects.