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Simple LED Fading Circuit using IC 555

Simple LED Fading Circuit using IC 555 is small project for LED light which are very cool and save power.

This LED light goes bright and then goes dim slowly.

We have used 555 IC chip and few other circuit parts which are very easy to make.

Circuit Diagram:

Parts List:

CategoryComponentQuantity
Resistors
47k 1/4W CFR1
330Ω 1W CFR1
Capacitors
Electrolytic 100μF 25V1
Semiconductors
IC 5551
Transistor BC5471
Battery 9V1
LEDs3

How to Build:

Circuit Functions:

555 IC work by charge and discharge of 100µF capacitor C1 and 47k resistor R1.

When capacitor charge and discharge slow it make voltage at transistor base go up and down slow like an soft ON/OFF switch.

Because of this LED light slowly gets bright and then gets dim and this make nice fading look.

Formulas and Calculations:

Formulas and Calculations for LED Fading Circuit with 555 IC:

Timing Parts:

The LED fading time depend on 100µF capacitor C1 and 47k resistor R1.

To find time constant (τ) it uses:

τ = R × C

For R1 = 47,000 ohms and C1 = 100µF

τ = 47,000 × 100 × 10⁻⁶ = 4.7 seconds

Frequency:

This show how fast LED fade is in and out.

f = 1 / (2 × τ)

So,

f = 1 / (2 × 4.7) = 0.106 Hz

Transistor Base Resistor R2:

To turn transistor ON we need base resistor R2.

Use ohms law:

IB = (VCC − VBE) / R2

where:

This calculation help pick right values for fading speed and transistor working.

We can change resistor or capacitor to make LED fade faster or slower.

Conclusion:

This article show how to make nice LED fading effect using old 555 IC and BC547 transistor.

Hobby people can start learning how parts work together in this circuit.

It helps to make fun light projects and bring some magic in electronics.

References:

LMC555 Fading led problem

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