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Simple 10V Switching Power Supply Circuit with IC LM5007

A switching regulator is a great circuit for changing power, skillfully controlling voltage levels by quickly turning a power transistor on and off.

The IC LM5007 is a special high voltage buck regulator made for situations where you need to lower voltage efficiently from a wide range of input voltages.

This built-in step-down switching regulator includes all the important parts to make a reliable and budget friendly switching regulator circuit.

The simple 10V Switching Power Supply Circuit using the LM5007 provides a steady 10V DC output from an input voltage range of 12V to 72V DC making it perfect for both industrial and automotive uses.

Also the LM5007 IC has a maximum output current limit of 700mA.

Circuit Working:

Parts List:

ComponentValueQuantity
Resistors (1/4W)
R1200k1
R2100k1
R33k1
R41k1
R51
Capacitors
C1PPC 1µF 100V1
C2, C3Ceramic 0.1µF2
C4Ceramic 0.01µF1
C5PPC 15µF 100V1
Semiconductors
ICIC1 LM50071
D1Diode 1N40071
Inductor
L1Inductor Coil 100µH1

The IC LM5007 acts like a buck converter, which means it takes a higher direct current voltage and lowers it to a steady 10V output.

Before the voltage gets to the integrated circuit, it passes through capacitors C1 and C2 to make sure everything is stable.

The LM5007 IC works by quickly turning its internal MOSFET on and off at a high speed, which helps send energy to the output through inductor L1.

Resistor R1 helps set up the conditions needed for the circuit to start, while resistor R2 is important for controlling how long the circuit stays off.

Capacitor C3 is used as a decoupling capacitor to improve how well the circuit works.

The fast switching of the internal MOSFET helps move energy efficiently through inductor L1.

Diode D1 is to protect the circuit from any sudden voltage spikes that might cause harm.

The output voltage is kept steady by a resistor divider made up of R3 and R4 and capacitor C5 helps smooth out the final output signal.

Additionally the pairing of resistor R5 and capacitor C5 forms a filter network that boosts the overall performance.

Formulas with Calculations:

Below are the formulas with calculations in Simple 10V Switching Power Supply Circuit with IC LM5007:

Output Voltage Calculation:

The output voltage Vout​ is determined by resistors R3 and R4:

Vout = 1.225V × (1 + R3 / R4)

where,

Substituting values:

Vout = 1.225V × (1 + 3000 / 1000)

Vout = 1.225V × (1 + 3)

Vout = 1.225V × 4

Vout = 10V

Inductor Selection Formula:

L = (Vin – Vout) × D / (fs × Iout)

where,

For practical purposes a 100µH inductor is chosen

Output Capacitor Selection Formula:

C = Iout / (8 × fs × Vripple)

where,

For a C5 15µF capacitor ripple is kept low.

How to Build

To build a Simple 10V Switching Power Supply Circuit with IC LM5007 follow the below mentioned steps:

Conclusion:

This Simple 10V Switching Power Supply Circuit with IC LM5007, which uses the LM5007 effectively reduces voltage from a broad input range of 12V to 72V.

The circuit ensures steady voltage regulation with very little power loss making it perfect for industrial power supplies, automotive uses and embedded systems that need a 10V power source.

References:

LM5007 75-V, 0.5-A DC/DC Buck Converter With 80-V Integrated Power MOSFET

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