Step-Up Converter Circuit: 6V to 15V Boost Regulator

The Step-Up Converter Circuit: 6V to 15V Boost Regulator is made to turn a 6V DC input into a powerful 15V DC output using the smart IC LM2585 switch mode regulator chip.

The IC LM2585 is a fantastic chip designed for boosting voltage.

You can use it in lots of different ways, like in flyback converters, boost converters, forward converters and systems that need several outputs.

One best thing about this chip is that it has a built-in switch that can handle currents up to 3A.

This makes it super useful when you want to get higher voltages from a lower voltage source.

Circuit Working:

Parts List:

The IC LM2585 is a special kind of device called a switching regulator that increases the input voltage from 6V to 15V.

The working of the circuit is mentioned below:

When the internal switch in the LM2585 is turned on electricity flows through a part called an inductor L1, which saves energy in its magnetic field.

When the switch turns off the energy stored in L1 creates extra voltage that adds to the input voltage.

This makes the diode D1 work, sending energy to the output capacitor C1.

This capacitor is super important because it helps keep the output voltage steady at 15V DC and capacitor C4 is for input voltage.

To make sure the output stays at a constant 15V, a feedback system with resistors R1 and R2 changes how long the switch stays on and off.

The circuit also has capacitors C2, C3 and C4 to help with filtering and stability which reduces voltage changes and makes the system respond better to any changes.

Formulas with Calculations:

Below are the formulas with calculations for Step-Up Converter Circuit: 6V to 15V Boost Regulator:

Output Voltage Calculation:

The output voltage vout is determined using the feedback resistor divider equation:

vout = vref * (1 + R1/R2)

where,

• vref reference voltage is 1.23V
• R1 is 56k ohm
• R2 is 4.7k ohm

substituting the values

vout = 1.23 * (1 + 56k/4.7k)

vout = 1.23 * (1 + 11.91)

vout = 1.23 * 12.91

vout = 15.87V

Approximating the output voltage is around 15V DC

Inductor selection:

The inductor l is selected according to the suggestions in the LM2585 datasheet and the needed output power.

When the switch is on the inductor collects energy and when the switch is off it releases that energy.

The usual formula for calculating inductance is:

l = (vin – vswitch) * d / (fsw * ipeak)

where,

• vin is 6V input voltage
• vswitch is 1V voltage drop across internal switch
• d duty cycle is approximated from

d = 1 – vin/vout

d = 1 – 6/15

d = 1 – 0.4

d = 0.6

• fsw is 100khz switching frequency
• ipeak is estimated from load current requirements from the calculations and standard values 22uh is selected for this circuit

How to Build:

To build a Step-Up Converter Circuit: 6V to 15V Boost Regulator follow the below mentioned steps:

• Assemble all the components as mentioned in the above circuit diagram
• Connect pin 1 of IC1  LM2585 to GND through resistor R3 and capacitor C2
• Connect pin 2 of IC1 between resistors R1 and R2
• Connect pin 3 of IC1to GND.
• Connect pin 4 between the junction of pin 5 and inductor coil L1
• Connect pin 5 of IC1 between the junction of Vin 6V DC and inductor coil L1
• Connect diode D1 between one terminal of L1 inductor coil and one terminal of resistor R1
• Connect capacitor C1 positive to Vout 15V DC and negative of capacitor connect to GND
• Connect capacitor C3 from pin 5 of IC1 and GND
• Connect capacitor C4 positive to Vin 6V DC and negative to GND

Conclusion:

This Step-Up Converter Circuit: 6V to 15V Boost Regulator is an easy and efficient method to increase a 6V DC input to a steady 15V DC output using the LM2585 integrated circuit.

It works well, needs only a few parts and is great for things like battery operated devices, car electronics and portable gadgets.

You can also tweak the output voltage by changing the resistor divider network to fit your specific needs.

References:

LM2585 4-V to 40-V, 3-A Step-Up Wide VIN Flyback Converter