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Simple 5V Step-Up Converter Circuit using IC LTC3440

A boost converter is a special kind of power converter that changes a lower DC voltage into a higher one.

This is really helpful for battery powered devices because sometimes the battery voltage is lower than what the device needs.

This Simple 5V Step-Up Converter Circuit uses the LTC3440 chip to change an input voltage between 2.7V and 4.2V into a steady 5V output.

The IC LTC3440 is super efficient working at up to 96% and can provide an output current of up to 600mA.

Also, it has a built-in oscillator that can be synchronized and adjusted to work between 300 KHz and 2 MHz.

This makes it great for powering microcontrollers, sensors and other electronic parts with just one lithium-ion battery.

Circuit Working:

Parts List:

Component TypeValue/Part NumberQuantity
Resistors (1/4W)619k1
200k1
15k1
60.4k1
1M1
CapacitorsCeramic 1.5nF1
Ceramic 0.1µF1
Electrolytic 10µF 25V, 22µF 25V1 each
SemiconductorsIC LTC34401
Schottky Diode MBRM120T31
Inductor10µH1
SwitchOn/Off Switch1

In this article the IC LTC3440 is a super efficient and quiet boost converter that works really well with low input voltages providing a steady 5V output.

Inductor L1 stores and moves energy helping to increase the voltage.

Schottky Diode D1 is important because it makes sure the current goes the right way protecting against damage from reverse voltage.

Resistors R1, R2 and R3 form a feedback network that helps keep the output voltage stable.

Capacitors C1, C2 and C3 are crucial for filtering and improving stability reducing voltage fluctuations.

C4 serves as the capacitor for the output filter.

Resistors R4 and R5 help set up how the LTC3440 switches on and off.

Switch S1 is used to turn the circuit on or off when needed.

Formulas with Calculation:

Below are the formulas with calculations for Simple 5V Step-Up Converter Circuit using IC LTC3440:

Output voltage (Vout) is determined using the feedback resistor network:

Vout = 1.23V * (1 + R1/R2)

where,

Substituting values:

Vout = 1.23V * (1 + 619k/200k)

Vout = 1.23V * (1 + 3.095)

Vout = 1.23V * 4.095

Vout = 5V

The formula calculates the output voltage based on the resistor divider network, which provides feedback to the LTC3440 to regulate and maintain the desired 5V output.

The LTC3440s switching speed is determined by its built-in oscillator and can be improved by choosing the right passive parts.

How to Build:

To build a Simple 5V Step-Up Converter Circuit using IC LTC3440 follow the below steps for connections and assembling:

Conclusion:

This Simple 5V Step-Up Converter Circuit using IC LTC3440 is an easy and efficient way to increase lower voltages.

It is perfect for devices that run on batteries as it converts power effectively while wasting very little energy.

By choosing the right component values the circuit can provide a steady and dependable 5V output making it great for powering microcontrollers, sensors and other electronic gadgets.

References:

LTC3440 Micropower Synchronous Buck-Boost DC/DC Converter

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