Simple LED Circuit

Want to light an LED using a battery?

This Simple LED Circuit using 9V Battery shows how.

It is the first step to learn electronics and current flow.

Just with one battery, one resistor and one LED.

We can make it in few minutes and see our LED glow bright.

Circuit Working:

Parts List:

Component	Specification / Value	Quantity
Resistor	350Ω	1
Semiconductors	2V Red LED	1
	9V DC Battery	1

The 9V battery gives power to LED through a resistor.

LED lights only when current flows in correct direction.

Resistor controls the current going to LED.

Without resistor a LED will burn because current is too high.

Formula with Calculation:

The formula for Simple LED Circuit.

Battery voltage = 9V

LED voltage drop = 2V (red LED)

Required current for LED = 20mA = 0.02A

Voltage drop across resistor = 9 – 2 = 7V

Resistor value R = V / I = 7 / 0.02 = 350 ohms

So we used R1 = 350Ω resistor.

How to Build:

To build a Simple LED Circuit follow the below steps:

• Gather all the parts as in circuit diagram.
• Connect positive (+) terminal of 9V battery to one end of resistor R1.
• Connect other end of resistor to LED anode.
• Connect LED cathode to negative (-) terminal of battery.

Conclusion:

This Simple LED Circuit is very easy to make.

It helps beginners to learn about LED polarity and resistor use.

Always use resistor to protect LED from high current.

References:

How can I make a simple circuit using a 9V battery and an LED light?