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Simple 1.5V Single Cell LED Flasher Circuit

In our previous article, we made a Simple 1.5V White LED Flasher Circuit using transistors and ferrite coil, but in this article we have design a Simple 1.5V Single Cell LED Flasher Circuit without ferrite coil.

This circuit works only with one 1.5V battery cell, so it is very useful for small battery projects and simple battery operated use.

Moreover, this circuit uses two transistors, few resistors and capacitors for making the LED blink continuously, because the design is very simple, beginners can easily make it and test it on breadboard or PCB.

Also, this circuit is very good for learning transistor switching and capacitor charging working concept.

Circuit Working:

Simple 1.5V Single Cell LED Flasher Circuit Diagram

Parts List:

ComponentsValuesQuantity
Resistors (All resistors are 1/4 watt)100k, 56Ω1 each
820Ω2
Capacitors Ceramic 0.01uF1
Electrolytic 10uF 25V, 100uF 25V1 each
Transistor NPN BC5471
Transistor PNP BC557 1
LED White LED 3mm 1
1.5V AA / Pencil Cell1

First, when we connect the 1.5V battery cell, resistor R1 gives bias current to transistor Q1 and as a result, Q1 starts conducting.

Next, capacitor C2 starts charging slowly through the connected path and because of this charging action, transistor Q2 receives base drive through resistor R2 and capacitor C1.

Then, Q2 turns ON and current flows through LED and resistor R4, therefore, the LED glows.

After that, capacitor C3 charges and discharges through resistor R3 and this action changes the bias condition of Q2.

Consequently, Q2 turns OFF after a short time and the LED turns OFF.

Again the capacitors recharge and discharge in cycle and hence, the LED continues blinking again and again.

So, in simple words the charging and discharging of capacitors control the ON and OFF switching of the transistors and because of this, the LED flashes.

Formulas with Calculations:

  1. Basic timing formula:

T = 0.693 × R × C

where:

Example for calculation using C3 and R3:

R3 = 56 ohm
C3 = 100 uF = 100 × 10^-6 F

T = 0.693 × 56 × 100 × 10^-6
= 0.00388 seconds

This means the time is about 0.00388 second where the circuit works very fast and changes ON/OFF quickly

Now for slower blinking, capacitor C2 plays an important role.

Using R1 and C2:

R1 = 100000 ohm
C2 = 10 uF = 10 × 10^-6 F

T = 0.693 × 100000 × 10 × 10^-6
T = 0.693 seconds

So, the LED blinking interval is around 0.7 second, this means the LED flashes nearly once every second.

2. LED current calculation:

Use Ohms law:

I = V / R

For LED resistor R4:

I = 1.5 / 820
I = 0.00183 A
I = 1.83 mA

So, the LED current is about 1.8 mA which is safe for low power blinking.

How to Build:

To build a Simple 1.5V Single Cell LED Flasher Circuit following steps are required for connections:

Conclusion:

This Simple 1.5V Single Cell LED Flasher Circuit is simple, low-cost and easy to build project.

The circuit works well with a single battery cell, so it is perfect for small electronic projects and learning purposes.

Also, by changing resistor and capacitor values, we can change the blinking speed easily.

Therefore, this circuit is an excellent beginner project for understanding transistor switching and timing circuits.

References:

Datasheet BC547

Datasheet BC557

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