Boost converter changes small DC voltage to big voltage; it is good for battery devices because battery voltage sometimes is less than device needs.
This 5V Step-Up Converter Circuit using IC LTC3440 changes input 2.7V to 4.2V into steady 5V output and LTC3440 IC is very efficient up to 96% and give up to 600mA current.
Also, it has built-in oscillator and can adjust from 300 KHz to 2 MHz and it is useful at power microcontrollers, sensors and other electronics with one lithium battery.
Circuit Working:
Parts List:
| Components | Values | Quantity |
|---|---|---|
| Resistors (All resistors are 1/4 watt unless specified) | 619k | 1 |
| 200k | 1 | |
| 15k | 1 | |
| 60.4k | 1 | |
| 1M | 1 | |
| Capacitors | Ceramic 1.5nF | 1 |
| Ceramic 0.1µF | 1 | |
| Electrolytic 10µF 25V, 22µF 25V | 1 each | |
| Semiconductors | IC LTC3440 | 1 |
| Schottky Diode MBRM120T3 | 1 | |
| Inductor 10µH | 1 | |
| Switch On/Off Switch | 1 |
To begin with, LTC3440 is efficient and quiet a boost converter, it works with low voltage input and gives steady 5V output.
Inductor L1 store and move energy to raise voltage and Schottky diode D1 guide gives current right way and stop reverse voltage damage.
Then R1, R2 and R3 make feedback network to keep output stable and R4 and R5 control how LTC3440 IC switch is ON and OFF.
After that, C1, C2 and C3 filter and keep voltage steady and C4 is output filter capacitor.
Finally, switch S1 turn circuit ON or OFF.
Formulas:
Here is simple formulas for 5V Step-Up Circuit with LTC3440:
Output voltage (Vout) = 1.23V × (1 + R1 / R2)
where,
- Vout is the output voltage
- 1.23V is internal reference voltage of LTC3440
- R1 is 619k ohm resistor
- R2 is 200k ohm resistor
How to Build:
To build a 5V Step-Up Converter Circuit using IC LTC3440 follow the below steps for connections and assembling:
- First, connect pin 1 of LTC3440 IC1 to GND through resistor R4.
- Next, connect pin 3 of IC1 to one end of inductor L1 and other end of L1 to pin 4 of IC1.
- Then connect pin 5 of IC1 to GND.
- Also, connect anode of diode D1 between pin 4 and pin 6 of IC1.
- Now connect pin 7 of IC1 to input voltage 2.7V to 4.2V
- After that, connect one terminal of capacitor C2 to pin 8 of IC1 and other terminal to GND.
- Further, connect switch S1 between junction of pin 8 and capacitor C2 and GND.
- Then connect one terminal of capacitor C3 to pin 7 of IC1 other terminal to GND an also connect resistor R5 between junction of pin 7 and capacitor C3 and one terminal of switch S1.
- Connect pin 9 of IC1 between resistors R1 and R2 and connect capacitor C1 and resistor R3 in series from pin 10 of IC1 to junction between R1 and R2.
- Finally, connect capacitor C2 from 5V output to GND.
Conclusion:
To conclude, this 5V Step-Up Converter Circuit using the LTC3440 efficiently raises low voltages with a simple design; also it suits battery-powered devices because it wastes very little energy.
Hence, with right parts it gives steady 5V output which is good for microcontrollers, sensors and other devices.