LED lights have gained a lot of popularity recently.
Another name for them is LED bulbs or solid state lighting.
Due to their significant lower power consumption i.e between 0.5 and 3 watts compared to other bulbs these lights are excellent for reducing electricity costs.
These bulbs were not as bright as some ten year ago, but you can still make your own simple LED bulb circuit using this tutorial.
We will discuss how to assemble your LED lightbulb with various color options along with its advantages.
What is a LED Bulb Circuit:
An LED bulb circuit is an electrical circuit that supplies power and regulates the LED light bulbs
LED lights use semiconductor technology to create light making them more energy efficient than standard incandescent or fluorescent bulbs.
Converting electrical power into light, controlling current and offering extra features like color shifting or dimming are all handled by the components inside an LED bulb.
Circuit Working:

Parts List:
Category | Component | Quantity |
---|---|---|
Resistors | 1M 1/4 W | 2 |
100Ω 1W | 3 | |
Capacitors | PPC 0.33µF 400V | 2 |
Electrolytic 47µF 100V | 1 | |
Semiconductors | Diode 1N4007 | 8 |
LEDs 30mA 5mm | 9 |
Every year the power and light brightness of LEDs grow due to their rapid technological advancement.
White LEDs are preferred choice for many applications which offer various light temperatures from warm white resembling conventional bulbs to daylight 2700 to 10,000k.
The choice between point and diffuser LEDs further extends to different radiation angles ranging from 10° to 150°.
As technology progresses the price of LEDs continues to decline accompanied by an increase in luminous efficiency.
An online tool is available to make the conversion from brightness to light flux easy.
Power Supply:
A sufficient power source is necessary when using LED bulbs that are powered by the mains.
Because transformers are not the best option for low power and tiny sizes capacitance based power supplies are often used.
The best class X2 capacitor is one with an AC voltage of 250V which is used to reduce inrush current with a series resistance of 220Ω to 2.2kΩ.
After turning off, a parallel security resistor of about 1M ensures capacitor discharge.
A tiny bridge diode rectifies the lower voltage.
With a common LED size of 5mm an online tool allows for calculating component values for LED bulbs.
Formulas and Calculations:
Following are the formulas with calculations for Simple LED Bulb Circuit:
Here we can estimate the current output of a transformerless power supply with a 0.33uF capacitor for two common mains frequencies: 50Hz and 60Hz.
Here is the calculation mentioned below:
Capacitance (C): 0.33 microFarads (uF) = 0.33 x 10-6 Farads (F)
Formula: Xc = 1 / (2 * π * f * C)
where,
- Xc is the capacitive reactance in ohms Ω
- π (pi) is a mathematical constant around 3.14159
- f is the mains frequency in hertz Hz
Calculations:
For 50Hz Mains:
- Xc_50Hz = 1 / (2 * π * 50Hz * 0.33 x 10-6F)
- Xc_50Hz = 9.55 kΩ (kilo-ohms)
For 60Hz Mains:
- Xc_60Hz = 1 / (2 * π * 60Hz * 0.33 x 10-6F)
- Xc_60Hz = 7.96 kΩ (kilo-ohms)
We can calculate the current using the following formula as the capacitor serves largely as a reactance in the circuit:
I = Vin / Xc
where,
- I is the current in milliamps mA
- Vin is the mains voltage
Important Reminder:
Not all circuit factors are taken into account by this simple technique.
Also one should never measure mains voltage yourself for safety reasons.
Assuming a typical mains voltage of 120V (US) or 230V (Europe) here is a rough estimate of the current output:
- For 50Hz (120V or 230V): I = Vin / Xc_50Hz = 12.6 mA (120V) or 24 mA (230V)
- For 60Hz (120V or 230V): I = Vin / Xc_60Hz = 15.1 mA (120V) or 29 mA (230V)
Note:
These are only estimates because of safety margins, power dissipation and capacitor quality the actual current output might be less.
For the majority of LEDs a transformerless power supply with a 0.33uF capacitor most certainly wont produce enough current.
How to Build:
To build Simple LED Bulb Circuit follow the below steps:
LED Selection:
- Choose the desired LED color, quantity and characteristics (brightness, angle, current).
Power Supply Design:
- Calculate the power supply type based on the LED quantity and power requirements.
- For low power use a capacitance based power supply with an X2 capacitor
- Formula: Q = CV
- where Q is charge, C is capacitance and V is voltage.
Resistors Calculation:
- Select a series resistor 220Ω to 2.2k to limit inrush current
- Ohms Law: R = V/I
- where R is resistance, V is voltage and I is current
Safety Measures:
- A parallel security resistor of about 1M must be added to help the capacitor discharge.
- Add a fuse or fusible resistor by protecting the input
Rectification:
- Use a small bridge diode to rectify the reduced voltage.
LED Connection:
- Use a small bridge diode to rectify the reduced voltage.
- LEDs are specially designed for a current of 20mA.
- Calculate the capacitor value using the
- formula: C = I * Δt / ΔV
- where C is capacitance, I is current, Δt is time and ΔV is voltage.
- LEDs are connected in series without changing component values up to a certain quantity around 20mA.
- For larger quantities adjust the capacitor capacity.
Construction:
- Connect the components on a circuit board ensuring proper insulation and spacing.
- Add the LEDs into the chosen base or socket.
- Use electrolyte to improve the source, removing stroboscopic effects and protecting against inrush currents for better performance.
Safety Precautions:
- Follow safety measures when working with mains voltage.
- Protect conductive parts to prevent electric shock.
- Display a warning about the lack of galvanic isolation and the associated risks.
- Design the circuit at your own risk.
Note:
- Actual values may differ depending on the components used this article offers an overall summary.
- Always verify that component ratings match to safety regulations and if necessary seek an expert advice.
- There are risks involved in building electrical gadgets thus care should be used at every steps.
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