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Automatic PIR Motion Sensor Light Circuit

Last updated on 1 January 2026 by Admin-Lavi Leave a Comment

This project explains about a complete Automatic PIR Motion Sensor Light Circuit.

It is very useful for home and outdoor lighting, because the circuit uses a PIR sensor.

Whenever motion is detected the light turns ON automatically.

After some time, the light turns OFF and therefore, power is saved.

Also, through this circuit the human effort is reduced.

Circuit Working:

Automatic PIR Motion Sensor Light Circuit Diagram

Parts List:

ComponentsValueQuantity
Resistors (All resistors are 1/4 watt)1k2
4.7k1
1M1
100k1
CapacitorsElectrolytic 330uF 25V1
Electrolytic 47uF 25V1
Ceramic 0.01uF1
SemiconductorsTransistor BC547 NPN1
Transistor BC557 PNP1
MOSFET IRLZ44N1
LEDs standard indicator LEDs2
12V LED1
Diode 1N41481
Diode 1N40071
PIR Motion Sensor Module1
Power Supply 12V DC1

At first the PIR sensor keeps watching for motion.

Normally, PIR output is LOW, so transistor Q1 BC547 stays OFF.

When motion comes then PIR output becomes HIGH.

Then current goes to base of Q1 through resistor R1 and so Q1 turns ON.

LED1 glows and shows motion detected.

After that Q1 gives signal to Q2 BC557 through resistor R3.

Then Q2 turns ON and capacitor C1 starts charging slowly.

Next, voltage reaches MOSFET Q3 gate through resistor R6.

So the MOSFET turns ON and now the LED load turns ON.

LED3 shows load ON condition.

Meanwhile the capacitor C1 stores charge and even when motion stops, C1 discharges slowly through resistor R4.

Because of this the MOSFET stays ON for some time and this gives delay before light OFF.

Finally, when capacitor voltage becomes low the MOSFET turns OFF and hence the light turns OFF automatically.

Formula with Calculation:

  1. Base resistor calculation for Q1:

R1 = (Vout of PIR โ€“ 0.7) / Ib

Assuming PIR output = 3V

Base current Ib = 0.5mA

R1 = (3 โ€“ 0.7) / 0.0005

R1 = 4600 ohm

Nearest standard value used in our circuit is 4.7k

2. Timing delay calculation using R4 and C1:

Delay time T = R4 x C1

  • R4 is 1M ohm
  • C1 is 330uF

T = 1,000,000 x 330 x 10^-6

T = 330 seconds approximately

How to Build:

To build a Automatic PIR Motion Sensor Light Circuit follow the below steps:

  • Gather all the parts as shown in circuit diagram.
  • PIR Sensor Vcc pin connect to +12V.
  • GND pin connect to ground.
  • OUT pin connect to base of Q1 through resistor R1.
  • BC547 transistor Q1 base pin connect to R1.
  • Emitter pin connect to ground.
  • Collector pin goes to LED1 and R1.
  • BC557 transistor Q2 emitter pin goes to +12V.
  • Base connects between collector of Q1 and LED1 through resistor R3.
  • Collector connects to diode D1.
  • IRLZ44N MOSFET Q3 gate pin goes from R6.
  • Drain pin connects to load and LED3.
  • Source pin connect to ground.
  • Capacitors C1 positive connects to diode D1 output.
  • C1 negative goes to ground.
  • C2 and C3 connected across supply for noise filtering.
  • Diode D1 1N4148 connected for timing isolation.
  • Diode D2 1N4007 across load for protection.

Conclusion:

This Automatic PIR Motion Sensor Light Circuit is simple and reliable.

It is good for home, corridor and outdoor places.

The circuit saves electricity and gives more convenience and safety.

With small changes it can control high power lights also.

So, this project is very good for beginners and practical use.

References:

Implementation Motion Sensor On Automatic Lighting And Security

Filed Under: LED and Lamps, Sensors and Detectors

About Admin-Lavi

Lavi is a B.Tech electronics engineer with a passion for designing new electronic circuits. Do you have questions regarding the circuit diagrams presented on this blog? Feel free to comment and solve your queries with quick replies

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