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Home » Designing a 20W Audio Amplifier Circuit using IC LM1875

Designing a 20W Audio Amplifier Circuit using IC LM1875

Last updated on 5 August 2025 by Admin-Lavi Leave a Comment

IC LM1875 is nice audio power amp which works very good and is very efficient.

It gives 20W power with few extra parts.

The sound is clear with low distortion and is good for many audio uses.

Circuit is good for small home audio, powered speaker, music instrument amplifiers.

In this post for Designing a 20W Audio Amplifier Circuit using IC LM1875 we will make 20W audio amplifier using LM1875.

We can see how it work, with full part calculation.

In this article we will show steps to build circuit easily.

Circuit Working:

Designing a 20W Audio Amplifier Circuit Diagram using IC LM1875

Parts List:

Component TypeValue/SpecificationQuantity
Resistors (All resistors are 1/4 watt unless specified)180k1
10k1
22k1
1M1
1k1
1Ω1
CapacitorsCeramic 100nF2
Ceramic 0.22μF1
Electrolytic 22μF, 25V1
Electrolytic 1μF, 25V1
Electrolytic 220μF, 25V2
SemiconductorsIC LM18751
Fuse 2A2
4Ω Speaker1

This diagram show how 20W audio amp work with LM1875 chip.

Audio signal come in through R5 and C4 to pin 1 of non-inverting input.

R4 give DC bias to this input.

R1 and R2 make feedback loop.

Gain of amplifier uses formula with right values with gain is 19.

C2 and C3 clean noise from negative power.

C6 and C5 do same for positive power.

This keep circuit stable with less noise.

Output goes to 4 ohm speaker from pin 4.

R6 and C7 make Zobel network and help stop high frequency noise and keep amplifier stable.

F1 and F2 are fuses which protect power from too much current.

Heat sink are used to stop LM1875 from getting too hot.

Formulas with Calculations:

Formulas and Calculations for 20W Audio Amp with LM1875:

Voltage Gain:

Gain = 1 + (R1 / R2)

where,

  • R1 is 180k and R2 is 10k

Gain = 1 + (180k / 10k) = 19

Input Impedance:

Zin set by R5 and R4

R4 >> R5 → Zin = R5 = 1k

Output Power:

Pout = Vrms² / Rload

where,

Assume Vrms is 12.65V and Rload = 4 ohm

Pout = (12.65²) / 4 = 20W

Coupling Capacitor (C4):

Need to pass low audio frequency

Xc = 1 / (2πfC)

C = 1 / (2π × 20Hz × 1k) = 1μF

How to Build:

For Designing a 20W Audio Amplifier Circuit using IC LM1875 follow the below steps for connections and assembling:

  • Pin 1 of LM1875 connects positive of side of C4
  • C4 side connects one side of R5
  • Other side of R5 goes to Audio input
  • R3 connects between Pin 1 and positive of C4 to GND
  • R4 goes between negative of C4 and R5
  • Pin 2 connects one side of R2 and positive of C1
  • C1 connects negative side of GND
  • Pin 3 connects one side of Fuse2 and other side to –25V DC
  • C2 connects from pin 3 to GND
  • C3 positive side connects pin 3 and negative side goes to GND
  • Pin 4 goes one side of R1 and other side of R1 goes to pin 2
  • Pin 4 connects to one side of 4Ω speaker and other side goes to GND
  • R6 and C7 connects from pin 4 to GND (Zobel network)
  • Pin 5 connects one side of Fuse1 and other side to +25V DC
  • C6 connects from pin 5 to GND
  • C5 positive side connects to pin 5 and negative side connects to GND

Conclusion:

Designing a 20W Audio Amplifier Circuit using IC LM1875 is easy and works well.

It give clear sound with low noise and is good for many audio jobs.

Just follow calculations and steps to get strong and clean amplifier.

Choosing right parts and design is very important for good sound.

References:

LM1875 20W Audio Power Amplifier

Filed Under: Amplifier Circuits, Audio Circuits

About Admin-Lavi

Lavi is a B.Tech electronics engineer with a passion for designing new electronic circuits. Do you have questions regarding the circuit diagrams presented on this blog? Feel free to comment and solve your queries with quick replies

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