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Home » 5V Step-Up Converter Circuit using IC LTC3440

5V Step-Up Converter Circuit using IC LTC3440

Last updated on 13 August 2025 by Admin-Lavi Leave a Comment

Boost converter changes small DC voltage to big voltage.

It is good for battery devices because battery voltage sometimes is less than device needs.

This 5V Step-Up Converter Circuit using IC LTC3440 changes input 2.7V to 4.2V into steady 5V output.

LTC3440 IC is very efficient up to 96% and give up to 600mA current.

It has built-in oscillator and can adjust from 300 KHz to 2 MHz.

It useful at power microcontrollers, sensors and other electronics with one lithium battery.

Circuit Working:

5V Step-Up Converter Circuit Diagram using IC LTC3440

Parts List:

Component TypeValueQuantity
Resistors (All resistors are 1/4 watt unless specified)619k1
200k1
15k1
60.4k1
1M1
CapacitorsCeramic 1.5nF1
Ceramic 0.1µF1
Electrolytic 10µF 25V, 22µF 25V1 each
SemiconductorsIC LTC34401
Schottky Diode MBRM120T31
Inductor 10µH1
Switch On/Off Switch1

LTC3440 is efficient and quiet a boost converter.

Works with low voltage input and gives steady 5V output.

Inductor L1 store and move energy to raise voltage.

Schottky diode D1 guide gives current right way and stop reverse voltage damage.

R1, R2 and R3 make feedback network to keep output stable.

C1, C2 and C3 filter and keep voltage steady.

C4 is output filter capacitor.

R4 and R5 control how LTC3440 IC switch is ON and OFF.

Switch S1 turn circuit ON or OFF.

Formulas:

Here is simple formulas for 5V Step-Up Circuit with LTC3440:

Output voltage (Vout) = 1.23V × (1 + R1 / R2)

where,

  • Vout is the output voltage
  • 1.23V is internal reference voltage of LTC3440
  • R1 is 619k ohm resistor
  • R2 is 200k ohm resistor

How to Build:

To build a 5V Step-Up Converter Circuit using IC LTC3440 follow the below steps for connections and assembling:

  • Connect pin 1 of LTC3440 IC1 to GND through resistor R4.
  • Connect pin 3 of IC1 to one end of inductor L1 and other end of L1 to pin 4 of IC1.
  • Connect pin 5 of IC1 to GND.
  • Connect anode of diode D1 between pin 4 and pin 6 of IC1.
  • Connect pin 7 of IC1 to input voltage 2.7V to 4.2V
  • Connect one terminal of capacitor C2 to pin 8 of IC1 and other terminal to GND.
  • Connect switch S1 between junction of pin 8 and capacitor C2 and GND.
  • Connect one terminal of capacitor C3 to pin 7 of IC1 other terminal to GND.
  • Connect resistor R5 between junction of pin 7 and capacitor C3 and one terminal of switch S1.
  • Connect pin 9 of IC1 between resistors R1 and R2.
  • Connect capacitor C1 and resistor R3 in series from pin 10 of IC1 to junction between R1 and R2.
  • Connect capacitor C2 from 5V output to GND.

Conclusion:

This 5V Step-Up Converter Circuit using IC LTC3440 is easy and efficient to raise low voltages.

Perfect for battery powered devices because it wastes little energy.

With right parts it gives steady 5V output which is good for microcontrollers, sensors and other devices.

References:

LTC3440 Micropower Synchronous Buck-Boost DC/DC Converter

Filed Under: Power Supply Circuits

About Admin-Lavi

Lavi is a B.Tech electronics engineer with a passion for designing new electronic circuits. Do you have questions regarding the circuit diagrams presented on this blog? Feel free to comment and solve your queries with quick replies

Previous Post: « Boost Converter 12V to 120V DC Step-Up Circuit
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