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Home » Simple Charger Breakdown Alarm Circuit

Simple Charger Breakdown Alarm Circuit

Last updated on 3 August 2025 by Admin-Lavi Leave a Comment

In electronic system good charger circuit very important.

It give power to things like battery.

This Simple Charger Breakdown Alarm Circuit check charger working or not.

If problem found then buzzer makes sound.

So user know fast if charger fails and this stop battery from drain or damage.

It uses easy parts like transistor, resistor, diode, LED and buzzer which is cheap and simple to make.

Alarm work like safety and it tell user quick if charging is not okay.

Circuit Working:

Simple Charger Breakdown Alarm Circuit Diagram

Parts List:

ComponentValue/Specification
Resistors
1k 1/4 watt2
10k 1/4 watt1
Semiconductors
Transistors BC5572
Diode 1N40071
LED 5mm, 20mA1
Buzzer1
SPST Switch1

Simple Charger Breakdown Alarm Circuit uses transistor switch method.

Charger connect to circuit for input voltage.

When charger is ON it gives positive voltage and circuit works fine.

Resistor R1 1k and LED1 are together.

LED light ON mean charger is giving power.

Two PNP transistors like Q1, Q2 BC557 check charger status.

When charger is ON then base of Q1 stay low and Q1 is ON and is buzzer OFF.

Base of Q2 is also low with circuit stable.

If charger is OFF or fails then base voltage of Q1 and Q2 goes high because of R2 and with no input power.

Then Q1 and Q2 goes OFF, buzzer is ON with sound alert comes.

Diode D1 1N4007 stop reverse voltage and circuit is safe.

Switch SW1 controls buzzer if there is no alarm needed and turns SW1 OFF.

Circuit output connects to battery.

So if charger fails, alarm ring before battery gets into problem.

Formulas with Calculations:

LED Current Limiting Resistor R1 keeps LED safe from too much current.

It control how much current goes through LED.

Formula to find R1:

R1 = (V_in – V_LED) / I_LED

where:

  • V_in is the 12V for input voltage
  • V_LED is 2V for LED forward voltage
  • I_LED is 20mA = 0.02A for LED current

This resistor stop LED from burning out.

Calculation:

R1 Calculation LED Resistor:

R1 = (12V – 2V) / 0.02A = 10V / 0.02A = 500Ω

But in actual 1kΩ is used to keep current lower and protect LED better.

R3 Transistor Base Resistor:

This resistor helps transistor switch ON/OFF properly.

Formula:

R3 = (V_in – V_BE) / I_B

where:

  • V_in is 12V
  • V_BE is 0.7V for BC557
  • I_B is base current for I_C / h_FE

I_C = 50mA for buzzer

h_FE = 100

So:

I_B = 50mA / 100 = 0.5mA = 0.0005A

R3 = (12 – 0.7) / 0.0005 = 11.3 / 0.0005 = 22.6kΩ

In actual 1kΩ to 10kΩ resistor are usually used.

How to Build:

To build a Simple Charger Breakdown Alarm Circuit follow the below mentioned steps:

  • Gather all parts like in circuit diagram above
  • Connect collector of Q1 to GND.
  • Connect base of Q1 to collector of Q2.
  • Connect emitter of Q1 to one side of buzzer and other side of buzzer to positive supply.
  • Connect LED1 with resistor R1 from emitter of Q1 to positive supply.
  • Connect collector of Q2 to GND through resistor R2.
  • Connect base of Q2 to positive supply between D1 and SW1 through resistor R3.
  • Connect emitter of Q2 directly to positive supply.

Conclusion:

This Simple Charger Breakdown Alarm Circuit is easy and helpful.

It uses basic parts to give light LED and sound buzzer if charger stops working.

So user know fast and battery stay safe with no drain and with no damage.

It is cheap to make and good for hobby or professional use.

With this circuit user can check charger all time and fix the problem quick.

References:

Battery charger

Filed Under: Alarm Circuits

About Admin-Lavi

Lavi is a B.Tech electronics engineer with a passion for designing new electronic circuits. Do you have questions regarding the circuit diagrams presented on this blog? Feel free to comment and solve your queries with quick replies

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